c语言一维数组怎么快速排列
231
2022-11-07
Java综合整理堆排序 快速排序 归并排序
目录堆排序快速排序递归非递归归并排序递归非递归
堆排序
时间复杂度:0(N*log(N))
空间复杂度:0(1)
稳定性:不稳定
private static void heapSort(int[] arr) {
//建堆
crearHeap(arr);
for (int i = 0; i < arr.length-1; i++) {
int heapSize=arr.length-i;
swap(arr,heapSize-1,0);
heapSize--;
shiftDown(arr,heapSize,0);
}
System.out.println(Arrays.toString(arr));
}
private static void crearHeap(int[] arr) {
// 从后往前遍历(右边非叶子节点开始), 依次进行向下调整
for (int i = (arr.length-1-1)/2; i >=0 ; i--) {
shiftDown(arr,arr.length,i);
}
}
//向下调整,形成大堆
private static void shiftDown(int[] arr, int size, int i) {
int parent = i;
int child = parent*2+1;
while (child if (child +1< size && arr[child +1]> arr[child]){ child=child+1; } if (arr[child]>arr[parent]){ swap(arr,child,parent); }else { break; } parent=child; child=parent*2+1; }NYrAoCWEvp } //交换 private static void swap(int[] arr, int child, int parent) { int tmp =arr[child];NYrAoCWEvp arr[child] =arr[parent]; arr[parent]=tmp; } 快速排序 时间复杂度:O(N^ logN) 最坏的时候O(N^2) 和基准值密切相关 空间复杂度:0(logN) 最坏的时候O(N) 稳定性:不稳定 递归 private static void quick(int[] arr) { quickSortHelper(arr,0,arr.length-1); System.out.println(Arrays.toString(arr)); } private static void quickSortHelper(int[] arr, int left, int right) { if (left>=right){ //区间只有一个元素,或者零个元素 return; } int index = partition(arr,left,right); quickSortHelper(arr,left,index-1); quickSortHelper(arr,index+1,right); } private static int partition(int[] arr, int left, int right) { int i=left; int j=right; int baseValue=arr[right]; while (i while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp =arr[i]; arr[i]=arr[j]; arr[j]=tmp; } 非递归 public static void quickSortByLoop(int[] arr) { Stack stack.push(0); stack.push(arr.length-1); while (!stack.isEmpty()){ int right = stack.pop(); int left = stack.pop(); if (left>=right){ continue; } int index = partition(arr,left,right); //右子树 stack.push(index+1); stack.push(right); //左子树 stack.push(left); stack.push(index-1); } System.out.println(Arrays.toString(arr)); } private static int partition(int[] arr, int left, int right) { int baseValue =arr[right]; int i =left; int j =right; while (i while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp = arr[i]; arr[i] = arr[j]; arr[j] = tmp; } 归并排序 时间复杂度:O(NlogN) 空间复杂度:O(N) 如果是链表,可以为O(1) 稳定性:稳定 递归 public static void mergeSort(int[] arr){ mergeSortHelper(arr,0,arr.length); System.out.println(Arrays.toString(arr)); } private static void mergeSortHelper(int[] arr, int left, int right) { if (right-left<=1){ return; } int mid = (right+left)/2; mergeSortHelper(arr,left,mid); mergeSortHelper(arr,mid,right); merge(arr,left,mid,right); } private static void merge(int[] arr, int left, int mid, int right) { int cur1 =left; int cur2 =mid; //两个数组合并后的结果 int[] output=new int[right-left]; int outputIndex=0; while (cur1 if (arr[cur1]<=arr[cur2]) { output[outputIndex++] = arr[cur1++]; }else { output[outputIndex++] = arr[cur2++]; } } while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
if (child +1< size && arr[child +1]> arr[child]){
child=child+1;
}
if (arr[child]>arr[parent]){
swap(arr,child,parent);
}else {
break;
}
parent=child;
child=parent*2+1;
}NYrAoCWEvp
}
//交换
private static void swap(int[] arr, int child, int parent) {
int tmp =arr[child];NYrAoCWEvp
arr[child] =arr[parent];
arr[parent]=tmp;
}
快速排序
时间复杂度:O(N^ logN) 最坏的时候O(N^2) 和基准值密切相关
空间复杂度:0(logN) 最坏的时候O(N)
稳定性:不稳定
递归
private static void quick(int[] arr) {
quickSortHelper(arr,0,arr.length-1);
System.out.println(Arrays.toString(arr));
}
private static void quickSortHelper(int[] arr, int left, int right) {
if (left>=right){
//区间只有一个元素,或者零个元素
return;
}
int index = partition(arr,left,right);
quickSortHelper(arr,left,index-1);
quickSortHelper(arr,index+1,right);
}
private static int partition(int[] arr, int left, int right) {
int i=left;
int j=right;
int baseValue=arr[right];
while (i while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp =arr[i]; arr[i]=arr[j]; arr[j]=tmp; } 非递归 public static void quickSortByLoop(int[] arr) { Stack stack.push(0); stack.push(arr.length-1); while (!stack.isEmpty()){ int right = stack.pop(); int left = stack.pop(); if (left>=right){ continue; } int index = partition(arr,left,right); //右子树 stack.push(index+1); stack.push(right); //左子树 stack.push(left); stack.push(index-1); } System.out.println(Arrays.toString(arr)); } private static int partition(int[] arr, int left, int right) { int baseValue =arr[right]; int i =left; int j =right; while (i while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp = arr[i]; arr[i] = arr[j]; arr[j] = tmp; } 归并排序 时间复杂度:O(NlogN) 空间复杂度:O(N) 如果是链表,可以为O(1) 稳定性:稳定 递归 public static void mergeSort(int[] arr){ mergeSortHelper(arr,0,arr.length); System.out.println(Arrays.toString(arr)); } private static void mergeSortHelper(int[] arr, int left, int right) { if (right-left<=1){ return; } int mid = (right+left)/2; mergeSortHelper(arr,left,mid); mergeSortHelper(arr,mid,right); merge(arr,left,mid,right); } private static void merge(int[] arr, int left, int mid, int right) { int cur1 =left; int cur2 =mid; //两个数组合并后的结果 int[] output=new int[right-left]; int outputIndex=0; while (cur1 if (arr[cur1]<=arr[cur2]) { output[outputIndex++] = arr[cur1++]; }else { output[outputIndex++] = arr[cur2++]; } } while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp =arr[i]; arr[i]=arr[j]; arr[j]=tmp; } 非递归 public static void quickSortByLoop(int[] arr) { Stack stack.push(0); stack.push(arr.length-1); while (!stack.isEmpty()){ int right = stack.pop(); int left = stack.pop(); if (left>=right){ continue; } int index = partition(arr,left,right); //右子树 stack.push(index+1); stack.push(right); //左子树 stack.push(left); stack.push(index-1); } System.out.println(Arrays.toString(arr)); } private static int partition(int[] arr, int left, int right) { int baseValue =arr[right]; int i =left; int j =right; while (i while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp = arr[i]; arr[i] = arr[j]; arr[j] = tmp; } 归并排序 时间复杂度:O(NlogN) 空间复杂度:O(N) 如果是链表,可以为O(1) 稳定性:稳定 递归 public static void mergeSort(int[] arr){ mergeSortHelper(arr,0,arr.length); System.out.println(Arrays.toString(arr)); } private static void mergeSortHelper(int[] arr, int left, int right) { if (right-left<=1){ return; } int mid = (right+left)/2; mergeSortHelper(arr,left,mid); mergeSortHelper(arr,mid,right); merge(arr,left,mid,right); } private static void merge(int[] arr, int left, int mid, int right) { int cur1 =left; int cur2 =mid; //两个数组合并后的结果 int[] output=new int[right-left]; int outputIndex=0; while (cur1 if (arr[cur1]<=arr[cur2]) { output[outputIndex++] = arr[cur1++]; }else { output[outputIndex++] = arr[cur2++]; } } while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
i++;
}
while (i
j--;
}
if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp =arr[i]; arr[i]=arr[j]; arr[j]=tmp; } 非递归 public static void quickSortByLoop(int[] arr) { Stack stack.push(0); stack.push(arr.length-1); while (!stack.isEmpty()){ int right = stack.pop(); int left = stack.pop(); if (left>=right){ continue; } int index = partition(arr,left,right); //右子树 stack.push(index+1); stack.push(right); //左子树 stack.push(left); stack.push(index-1); } System.out.println(Arrays.toString(arr)); } private static int partition(int[] arr, int left, int right) { int baseValue =arr[right]; int i =left; int j =right; while (i while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp = arr[i]; arr[i] = arr[j]; arr[j] = tmp; } 归并排序 时间复杂度:O(NlogN) 空间复杂度:O(N) 如果是链表,可以为O(1) 稳定性:稳定 递归 public static void mergeSort(int[] arr){ mergeSortHelper(arr,0,arr.length); System.out.println(Arrays.toString(arr)); } private static void mergeSortHelper(int[] arr, int left, int right) { if (right-left<=1){ return; } int mid = (right+left)/2; mergeSortHelper(arr,left,mid); mergeSortHelper(arr,mid,right); merge(arr,left,mid,right); } private static void merge(int[] arr, int left, int mid, int right) { int cur1 =left; int cur2 =mid; //两个数组合并后的结果 int[] output=new int[right-left]; int outputIndex=0; while (cur1 if (arr[cur1]<=arr[cur2]) { output[outputIndex++] = arr[cur1++]; }else { output[outputIndex++] = arr[cur2++]; } } while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
swap(arr,i,j);
}
}
swap(arr,i,right);
return i;
}
private static void swap(int[] arr, int i, int j) {
int tmp =arr[i];
arr[i]=arr[j];
arr[j]=tmp;
}
非递归
public static void quickSortByLoop(int[] arr) {
Stack
stack.push(0);
stack.push(arr.length-1);
while (!stack.isEmpty()){
int right = stack.pop();
int left = stack.pop();
if (left>=right){
continue;
}
int index = partition(arr,left,right);
//右子树
stack.push(index+1);
stack.push(right);
//左子树
stack.push(left);
stack.push(index-1);
}
System.out.println(Arrays.toString(arr));
}
private static int partition(int[] arr, int left, int right) {
int baseValue =arr[right];
int i =left;
int j =right;
while (i while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp = arr[i]; arr[i] = arr[j]; arr[j] = tmp; } 归并排序 时间复杂度:O(NlogN) 空间复杂度:O(N) 如果是链表,可以为O(1) 稳定性:稳定 递归 public static void mergeSort(int[] arr){ mergeSortHelper(arr,0,arr.length); System.out.println(Arrays.toString(arr)); } private static void mergeSortHelper(int[] arr, int left, int right) { if (right-left<=1){ return; } int mid = (right+left)/2; mergeSortHelper(arr,left,mid); mergeSortHelper(arr,mid,right); merge(arr,left,mid,right); } private static void merge(int[] arr, int left, int mid, int right) { int cur1 =left; int cur2 =mid; //两个数组合并后的结果 int[] output=new int[right-left]; int outputIndex=0; while (cur1 if (arr[cur1]<=arr[cur2]) { output[outputIndex++] = arr[cur1++]; }else { output[outputIndex++] = arr[cur2++]; } } while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
while (i i++; } while (i j--; } if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp = arr[i]; arr[i] = arr[j]; arr[j] = tmp; } 归并排序 时间复杂度:O(NlogN) 空间复杂度:O(N) 如果是链表,可以为O(1) 稳定性:稳定 递归 public static void mergeSort(int[] arr){ mergeSortHelper(arr,0,arr.length); System.out.println(Arrays.toString(arr)); } private static void mergeSortHelper(int[] arr, int left, int right) { if (right-left<=1){ return; } int mid = (right+left)/2; mergeSortHelper(arr,left,mid); mergeSortHelper(arr,mid,right); merge(arr,left,mid,right); } private static void merge(int[] arr, int left, int mid, int right) { int cur1 =left; int cur2 =mid; //两个数组合并后的结果 int[] output=new int[right-left]; int outputIndex=0; while (cur1 if (arr[cur1]<=arr[cur2]) { output[outputIndex++] = arr[cur1++]; }else { output[outputIndex++] = arr[cur2++]; } } while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
i++;
}
while (i
j--;
}
if (i swap(arr,i,j); } } swap(arr,i,right); return i; } private static void swap(int[] arr, int i, int j) { int tmp = arr[i]; arr[i] = arr[j]; arr[j] = tmp; } 归并排序 时间复杂度:O(NlogN) 空间复杂度:O(N) 如果是链表,可以为O(1) 稳定性:稳定 递归 public static void mergeSort(int[] arr){ mergeSortHelper(arr,0,arr.length); System.out.println(Arrays.toString(arr)); } private static void mergeSortHelper(int[] arr, int left, int right) { if (right-left<=1){ return; } int mid = (right+left)/2; mergeSortHelper(arr,left,mid); mergeSortHelper(arr,mid,right); merge(arr,left,mid,right); } private static void merge(int[] arr, int left, int mid, int right) { int cur1 =left; int cur2 =mid; //两个数组合并后的结果 int[] output=new int[right-left]; int outputIndex=0; while (cur1 if (arr[cur1]<=arr[cur2]) { output[outputIndex++] = arr[cur1++]; }else { output[outputIndex++] = arr[cur2++]; } } while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
swap(arr,i,j);
}
}
swap(arr,i,right);
return i;
}
private static void swap(int[] arr, int i, int j) {
int tmp = arr[i];
arr[i] = arr[j];
arr[j] = tmp;
}
归并排序
时间复杂度:O(NlogN)
空间复杂度:O(N) 如果是链表,可以为O(1)
稳定性:稳定
递归
public static void mergeSort(int[] arr){
mergeSortHelper(arr,0,arr.length);
System.out.println(Arrays.toString(arr));
}
private static void mergeSortHelper(int[] arr, int left, int right) {
if (right-left<=1){
return;
}
int mid = (right+left)/2;
mergeSortHelper(arr,left,mid);
mergeSortHelper(arr,mid,right);
merge(arr,left,mid,right);
}
private static void merge(int[] arr, int left, int mid, int right) {
int cur1 =left;
int cur2 =mid;
//两个数组合并后的结果
int[] output=new int[right-left];
int outputIndex=0;
while (cur1 if (arr[cur1]<=arr[cur2]) { output[outputIndex++] = arr[cur1++]; }else { output[outputIndex++] = arr[cur2++]; } } while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
if (arr[cur1]<=arr[cur2]) {
output[outputIndex++] = arr[cur1++];
}else {
output[outputIndex++] = arr[cur2++];
}
}
while (cur1 output[outputIndex++] = arr[cur1++]; } while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
output[outputIndex++] = arr[cur1++];
}
while (cur2 output[outputIndex++] = arr[cur2++]; } for (int i = 0; i < right-left ; i++) { arr[left+i] = output[i]; } } 非递归 public static void mergeSortByLoop(int[] arr){ // gap 当前每个组中的元素个数. for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
output[outputIndex++] = arr[cur2++];
}
for (int i = 0; i < right-left ; i++) {
arr[left+i] = output[i];
}
}
非递归
public static void mergeSortByLoop(int[] arr){
// gap 当前每个组中的元素个数.
for (int gap =1;gap for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
for (int i = 0; i //相当于把两个长度为 gap 的相邻组进行了合并 int left =i; int mid =i+gap; int right=i+2*gap; if (mid > arr.length){ mid =arr.length; } if (right>arr.length){ right=arr.length; } merge(arr,left,mid,right); } } System.out.println(Arrays.toString(arr)); }
//相当于把两个长度为 gap 的相邻组进行了合并
int left =i;
int mid =i+gap;
int right=i+2*gap;
if (mid > arr.length){
mid =arr.length;
}
if (right>arr.length){
right=arr.length;
}
merge(arr,left,mid,right);
}
}
System.out.println(Arrays.toString(arr));
}
版权声明:本文内容由网络用户投稿,版权归原作者所有,本站不拥有其著作权,亦不承担相应法律责任。如果您发现本站中有涉嫌抄袭或描述失实的内容,请联系我们jiasou666@gmail.com 处理,核实后本网站将在24小时内删除侵权内容。
发表评论
暂时没有评论,来抢沙发吧~